[hline" 3) 5.6"X10^(-1)" moll "," 4) "2.8times10^(-4)" moll "^(-1)],[" 63."K_(sp)" of a salt "ZnCl_(2)" is "3.2times10^(-3)" its "P^(3)" is "],[[" 1) "2.3980," 2) "11.6020],[" 3) "2.6990," 4) do not calculated exactly "]]

K_(sp) of a salt ZnCl_(2) is 3.2 xx 10^(-8) its P^(H) is

The solubility of PbI_(2) is 1.3xx10^(-3)molL^(-1) . What is the K_(sp) for Pbl_(2) ?

If the solubility of MX_(2) ( a sparingly soluble salt is 2.5 xx 10^(-4) mol^(-1) . The value of K_(sp) of the salt would be

K_(sp) of the salt AB_(2) at 298 K is 4 times 10^(-11)M . A precipitate of AB_(2) is formed when equal volumes of which of the following solutions of A^(2+) and B^(-) are mixed? A) 2 times 10^(-4)M" "A^(2+) and 2 times 10^(-4)M" "B^(-)" B) 2 times 10^(-5)M" "A^(2+) and 2 times 10^(-3)M" "B^(-) C) 2 times 10^(-2)M" "A^(2+) and 2 times 10^(-3)M" "B^(-)

Simplify: 10^(-1)times10^(2)times10^(-3)times10^(4)times10^(-5)times10^(6)

In the reaction, A+3Brarr2C,(d[C])/(dt)=2xx10^(-4)"mol.L"^(-1).s^(-1) So , (-d[B])/(dt)("in mol.L"^(-1).s^(-1)) is -

CMC for soap is 10^(-4) and 10^(-3) molL^(-1) . What do you mean? What is Kraft temperature?

K_(sp) for lead iodate [Pb(IO_(3))_(2) is 3.2 xx 10^(-14) at a given temperature. The solubility in molL^(-1) will be

K_(sp) for lead iodate [Pb(IO_(3))_(2) is 3.2 xx 10^(-14) at a given temperature. The solubility in molL^(-1) will be

Calculate the solubility of Ca(OH)_(2) in 0.05MNaOH solution? K_(sp) = Ca(OH)_(2) = 1.3times10^(-6) (A) 4.6times10^(-3) B) 5.2times10^(-4) M C) 6.2times10^(-5) D) 3.4times10^(-6)