" asse ic dotangeABC appiniM such that "AM=(1)/(3)AC" ,Apoint Nistaken on the side "bar(CB)" suct "

Taken on side vec AC of a triangle ABC, a point M such that vec AM=(1)/(3)vec AC. A point N is taken on the side vec CB such that vec BN=vec CB then, for the point of intersection x vec AB and vec MN which of the following holds good?

In a right triangle ABC , right angled at C, P and Q are the points of the sides CA and CB respectively , which divide these sides in the ratio 2 : 1 Prove that 9AQ^(2)=9AC^(2)+4BC^(2)

In a right triangle ABC , right angled at C, P and Q are the points of the sides CA and CB respectively , which divide these sides in the ratio 2 : 1 Prove that 9BP^(2)=9BC^(2)+4AC^(2)

Choose the corect options. The magnetic induction at apoint distance 15 cm on the axis of a short bar magnet moment 0.5 Am^2 is A. 3 xx 10^-11 Wb//m^2 B. 3 xx 10^-8 Wb//m^2 C. 3 xx 10^-11 Wb//m^2 D. 3 xx 10^-5 Wb//m^2

The position vectors of the points A and B are 2vec(a)+vec(b) " and " vec(a)-3vec(b) . If the point C divides the line-segment bar(AB) externally in the ratio 1:2, then find the position vector of the point C. Show also that A is the midpoint of the line-segment bar(CB) .

squareABCD is a parallelogram. (A_(1)) and B_(1) are midpoints of the sides bar(BC) and bar(AD) respectively. If vec("AA")_(1)+vec(AB)_(1)=lambda vec(AC) then lambda = …………

In squareABCD , side BC|| side AD . Digonals AC and BD intersect each other at P . If AP=(1)/(3)AC then prove DP=(1)/(2)BP .

In squareABCD , side BC|| side AD . Digonals AC and BD intersect each other at P . If AP=(1)/(3)AC then prove DP=(1)/(2)BP .