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Find the equation of an ellipse hose axe...

Find the equation of an ellipse hose axes lie along the coordinate axes, which passes through the point (-3,1) and has eccentricity equal to `sqrt(2//5)dot`

A

`3x ^(2) + 5y ^(2) -15=0`

B

`5x ^(2) + 3y ^(2) -32=0`

C

`3x ^(2) + 5y ^(2) -32=0`

D

`5x^(2) + 3y ^(2) -48=0`

Text Solution

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The correct Answer is:
D
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TARGET PUBLICATION-CIRCLE AND CONICS -COMPETITIVE THINKING
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