int(xsinx)/(xcosx-sinx-1)dx=""+c...

`int(xsinx)/(xcosx-sinx-1)dx="_______"+c`

A

`-logabs(xsinx-cosx-1)`

B

`logabs(xsinx-cosx-1)`

C

`-logabs(xcosx-sinx-1)`

D

`logabs(xcosx-sinx-1)`

Text Solution

Verified by Experts

The correct Answer is:

C

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