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The component of vector A=a(x)hati+a(y)h...

The component of vector `A=a_(x)hati+a_(y)hatj+a_(z)hatk` and the directioin of `hati-hatj` is

A

`A_(x)-A_(y) +A_(z)`

B

`A_(x)+A_(y)+A_(z)`

C

`A_(x)-A_(y)`

D

`(A_(x) -A_(y))/(sqrt(2))`

Text Solution

Verified by Experts

The correct Answer is:
D

Magnitude of vector `vec A`
`=|bar A|=sqrt(A_(x)^(2) + A_(y)^(2)+A_(z)^(2))` Where `A_(x), A_(y) and A_(z)` are the magnitudes of the projections of `vec A` along the co-ordinate axes X,Y, and Z respectively.
`therefore vec r - vec j = vec i+(-vecj)`
The magnitude is `sqrt(1^(2)+1^(2)) = sqrt(2)`
`therefore` Component of the vector `vec A =(A_(x) - A_(y))/(sqrt(2))`
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