`CH_(3)-CH_(2)-overset(O)overset(||)(C )-OC_(2)H_(5) overset(Naoverset(**)(O)H)underset(H_(2)O^(**))rarr` Products of the above reaction contain

Options

A. `CH_(3)-CH_(2)-overset(O)overset(||)(C )-overset(**)(O^(-))`
B. `CH_(3)-CH_(2)-overset(O^(**))overset(||)(C )-O^(-)`
C. `CH_(3)CH_(2)-overset(**)(O)-H`
D. Both (a) and (b)

Explanation

To solve the given reaction, we need to analyze the reactants and the conditions under which the reaction takes place. The reaction involves a compound with a carbonyl group (C=O) and an ether group (–O–C2H5) in the presence of sodium hydroxide (NaOH) and water (H2O).

### Step-by-Step Solution:

1. **Identify the Reactant Structure**:
The given compound is CH3-CH2-C(=O)-O-C2H5. This structure consists of a carbon chain (ethyl group) attached to a carbonyl group (C=O) and an ether group (–O–C2H5).

2. **Nucleophilic Attack by Hydroxide Ion**:
In the presence of NaOH, the hydroxide ion (OH-) acts as a nucleophile and attacks the carbonyl carbon (C=O). This results in the formation of a tetrahedral intermediate.

3. **Formation of Tetrahedral Intermediate**:
The attack of the hydroxide ion leads to the formation of a tetrahedral intermediate where the carbonyl oxygen becomes negatively charged (alkoxide ion). The structure now looks like:
CH3-CH2-C(OH)(O-C2H5).

4. **Proton Transfer**:
In the next step, there is a proton transfer (H+ transfer) from the hydroxyl group (OH) to the ether oxygen (O-C2H5). This results in the formation of a hydroxyl group and the regeneration of the carbonyl group.

5. **Elimination of Ethanol**:
The tetrahedral intermediate collapses, leading to the elimination of ethanol (C2H5OH) as a leaving group. The product formed is:
CH3-CH2-C(=O)-OH.

6. **Final Product**:
The final product of this reaction is a carboxylic acid (specifically, butanoic acid) and an alkoxide ion (which is the result of the ether group losing a proton).

### Final Products:
The products of the reaction are:
- Butanoic acid (CH3-CH2-C(=O)-OH)
- Ethoxide ion (C2H5O-)

### Summary of Products:
The products of the above reaction contain:
1. Butanoic acid (CH3-CH2-C(=O)-OH)
2. Ethoxide ion (C2H5O-)