The van't Hoff factor for `BaCl_(2)` at 0.01 M concentration is 1.98. The percentage dissociation of `BaCl_(2)` at this concentration is :

Options

A. 49
B. 69
C. 89
D. 98

Answer

A

Explanation

`{:(,BaCl_(2),hArr,Ba^(2+),+,2Cl^(-)),("Initial","1 mole",,0,,0),("After disso. ",1-alpha,,alpha,,2alpha","):}`
"Total no. of particles "=1+2alpha
`i=1+2alpha`
`or alpha=(i-1)/(2)=(1.98-1)/(2)=(0.98)/(2)=0.4949%`.