Match the entries of column I with appropriate entries of coloumn II. Each entry in column I may have one or more than one correct option from column II. If the correct matches are A-p, s , B-r, C-p, q , D-s, then the correctly bubbled 4 `xx` 4 matrix should be as follows :
`{:(,"Column I",,"Column II"),((A),H_(3)PO_(3) overset(Delta)rarr,(p),"One of the products acts as a reducing agent."),((B),PCl_(3) + H_(2)O overset(Delta)rarr,(q),"One of the products is a tribasic non-reducing acid."),((C),NO_(2) + H_(2)O rarr,(r),"Dehydration"),((D),HNO_(3) + P_(4)O_(10) overset(Delta)rarr,(s),"In one of the products, central atom has +5 oxidation state."):}`

Explanation

To solve the matching problem between Column I and Column II, we will analyze each entry in Column I and determine which entries in Column II correspond to it based on the chemical reactions and properties described.

### Step-by-Step Solution:

1. **Analyze Entry A: H₃PO₃ (Phosphorous acid) heated**
- When H₃PO₃ is heated, it decomposes to form H₃PO₄ (Phosphoric acid) and PH₃ (Phosphine).
- PH₃ acts as a reducing agent because it can donate electrons.
- H₃PO₄ is a tribasic acid (it can donate three protons) and is non-reducing.
- Therefore, A matches with:
- **P**: "One of the products acts as a reducing agent." (PH₃)
- **Q**: "One of the products is a tribasic non-reducing acid." (H₃PO₄)
- **R**: "Dehydration" (H₃PO₃ can undergo dehydration to form H₄P₂O₇)

2. **Analyze Entry B: PCl₃ + H₂O heated**
- PCl₃ reacts with water to form H₃PO₃ and HCl.
- H₃PO₃ has a +3 oxidation state for phosphorus, and it can act as a reducing agent.
- H₃PO₃ is not a tribasic acid; it is a dibasic acid (it can donate two protons).
- Therefore, B matches with:
- **P**: "One of the products acts as a reducing agent." (H₃PO₃)
- **R**: "Dehydration" (H₃PO₃ can lose water to form HPO₂)

3. **Analyze Entry C: NO₂ + H₂O**
- NO₂ reacts with water to form HNO₃ (Nitric acid) and NO (Nitric oxide).
- NO acts as a reducing agent because it can be oxidized to NO₂.
- HNO₃ is a monobasic acid (it can donate one proton).
- Therefore, C matches with:
- **P**: "One of the products acts as a reducing agent." (NO)
- **R**: "Dehydration" (HNO₃ can undergo dehydration)
- **S**: "In one of the products, central atom has +5 oxidation state." (HNO₃ has nitrogen in +5 state)

4. **Analyze Entry D: HNO₃ + P₄O₁₀ heated**
- HNO₃ reacts with P₄O₁₀ to form HPO₃ and N₂O₅.
- Both HPO₃ and N₂O₅ have phosphorus and nitrogen in the +5 oxidation state.
- HPO₃ can undergo dehydration.
- Therefore, D matches with:
- **R**: "Dehydration" (HPO₃ can lose water)
- **S**: "In one of the products, central atom has +5 oxidation state." (both HPO₃ and N₂O₅)

### Final Matches:
- A: P, Q, R
- B: P, R
- C: P, R, S
- D: R, S

### Summary of Matches:
- A → P, Q, R
- B → P, R
- C → P, R, S
- D → R, S