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Why is geometrical isomerism not possibl...

Why is geometrical isomerism not possible in tetrahedral complexes having two different types of unidentate ligands coordinated with central metal ion ? .

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Assertion : Tetrahedral complexes having two different types of unidentate ligands coordinated with central metal ion will show geometrical isomerism . Reason : Geometrical isomerism arises in homoleptic complexes due to different possible geometric arrangement of the ligands .

The number of unidentate ligands in the complex ion is called

Geometrical isomerism is found in coordination compounds having coordination number:

Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. Which of the following complexes will show geometrical isomerism ?

Geometrical isomerism arises in heteroleptic complexes due to different possible geometrical arrangement of the ligands. Important examples of this behaviour are found with coordination number 4 and 6. Such isomerism is not possible for a tetrahedral geometry but it is possible for square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical square planar as well as octahedral complexes. Optical isomers are mirror images that cannot be superimposed on one another. These are called enantiomers. Optical isomerism is common in octahedral complexes involving bedentate ligands. Which one of the following statements is false ?

PRADEEP-CORDINATION COMPOUNDS-NCERT INTEXT QUESTIONS
  1. On the basis of the following observations made with aqueous solutions...

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  2. Write the formulas for the following coordination compounds: (a) Tet...

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  3. Write the IUPAC names of the following coordination compounds: (a)[P...

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  4. Why is geometrical isomerism not possible in tetrahedral complexes hav...

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  5. Draw structures of geometrical isomers of [Fe(CN)(4)(NH(3))(2)]^(Θ) .

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  6. Out of the following two coordination entities Which is chiral (optica...

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  7. The spin only magnetic moment of [MnBr(4)]^(2-) is 5.9 BM. Predict the...

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  8. Wrtie the formulas for the following coordination compounds: (i). Te...

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  9. Write the IUPAC names of the following coordiantion compounds: (i) [...

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  10. Indicate the type of isomerism exhibited by the following complexes an...

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  11. Give evidence that [Co(NH(3))(5)Cl]SO(4) and [Co(NH(3))(5)SO(4)]Cl are...

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  12. Explain on the basis of valence bond theory that [Ni(CN)(4)]^(2-) ion ...

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  13. [NiCl(4)]^(2-) is paramagnetic while [Ni(CO)(4)] is diamagnetic though...

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  14. [Fe(H2O)6]^(3+) is strongly paramagnetic whereas [Fe(CN)6]^(3-) is wea...

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  15. Explain [Co(NH3)6]^(3+) is an inner orbital complex whereas [Ni(NH3)6]...

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  16. Predict the number of unpaired electrons in the square planar [Pt(CN)4...

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  17. The hexaquo manganese(II) ion contains five unpaired electrons, while ...

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  18. Calculate the overall complex dissociation equilibrium constant for th...

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