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If 1 1/2 moles of oxygen combine with Al...

If `1 1/2` moles of oxygen combine with Al to form `Al_(2)O_(3)` the weight of Al used in the reaction is (Al=27)

A

2.7

B

54

C

40.5

D

81

Text Solution

Verified by Experts

The correct Answer is:
B
`4Al+3O_(2)rarr 2Al_(2)O_(3)`
3 moles of `O_(2)` combine with Al = 4 moles `=4xx27g=108g`
`therefore" 1.5 moles of "O_(2)" will combine with Al = 54 g."`
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