If 30 ml of `H_2` and 20 ml of `O_2` react to form water, what is left at the end of the reaction ?

Options

A. `"10 ml of "H_(2)`
B. `"5 ml of "H_(2)`
C. `"10 ml of "O_(2)`
D. `"5 ml of "O_(2)`

Answer

D

Explanation

`underset("2 ml")(2H_(2))+underset("1 ml")(O_(2))rarr2H_(2)O`
`"2 ml of "H_(2)" react with 1 ml of "O_(2)." Hence, 30 ml of "H_(2)" will react with 15 ml of "O_(2)`