Number of moles of `MnO_(4)^(-)` required to oxidise one mole of ferrous oxalate completely in acidic medium will be

Options

A. 7.5 moles
B. 0.2 moles
C. 0.6 moles
D. 0.4 moles

Answer

c

Explanation

`MnO_(4)^(-)+8H^(+)+5e^(-)(rarrMltn^(2+))+4H_(2)O`
`FeC_(2)O_(4)rarrFe^(2+)+C_(2)O_(4)^(23-)`
`Fe^(2+)rarrFe^(3+)+e^(-)`
`C_(2)O_(4)^(2-)rarr2CO_(2)+2e^(-)`
since one mole of `FeC_(2)O_(4)` loses 3 moles of electrons while one mole of `KMnO_(4)` accepts five moles of electrons therefore number of moles of `KMnO_(4)` required to oxidised one mole of `FeC_(21)O_(4)=3//5 =0.6` mole