Find the area of a rhombus whose perimeter is `80 m` and one of whose diagonal is `24 mdot`

Explanation

Area of rhombus`=1/2d_1xxd_2`
`a=1/4(80)`
`a=20cm`
`d_1=24cm`
`AC=24cm`
`AO=1/2(24)=12m`
Now Using pythagorus theoram,`OB^2=AB^2-OA^2`
`OB^2=20^2-12^2=16m`
Area of rhombus`=1/2(24)(32)=384cm^2`