35.sin7x+cos2x=-2

The least difference between the roots in the first quadrant in [0, pi/2] of the equation sin7x+cos2x=-2 is

The solution(s) of the equation sin7x+cos2x=-2 is/are (a) x=(2kpi)/7+(3pi)/(14),\ k in I (b) x=npi+pi/4\ k in I x=2npi+pi/2,\ k in I (d) none of these

The solution(s) of the equation sin7x+cos2x=-2 is/are x=(2kpi)/7+(3pi)/(14),\ k in I (b) x=npi+pi/4\ k in I x=2npi+pi/2,\ k in I (d) none of these

The equation a sin x+cos2x=2a-7 possesses a solution if

Prove the following: (frac(sinx-sin3x+sin5x-sin7x)(cosx-cos3x-cos5x+cos7x))=cot2x

If 3cos x!=2sin x, then the general solution of sin^(2)x-cos2x=2-sin2x is x

If 2 cos x ne 2 sin, x then the general solution of sin^(2)x-cos2x=2 sin 2x is

Solve : 3sin^2x+7cos^2x=6

Find common roots of the equations 2sin^2x+sin^2 2x=2 and sin2x + cos2x=tanx