An alloy of iron (54.7%) nickel (45%) and manganese (0.3%) has a density of 8.17 `g//cm^(3)`. How many iron atoms are there in a block of alloy measuring `10cmxx20cmxx15cm`?

Explanation

Volume of the block of alloy`=10020xx15cm^(3)`
=`3000cm^(3)`
Mass of the block `=300xx8.17g=24510g`
Mass of iron in the block `=(54.7)/(100)xx24510=13406.97g`
Number of iron atoms in the block `=("Mass")/("Atomic mass")xx6.023xx10^(23)`
`=1.442xx10^(26)`