Evaluate the following. `(sec^2(90-theta)-cot^2 theta)/(2(sin^(2)25^@+sin^(2) 65^@))-(2cos^(2)60 tan^(2)28^@ tan^(2)62)/(3(sec^2 43^@-cot^(2)47^@))`

Evaluate the following.(sec^(2)(90-theta)-cot^(2)theta)/(2(sin^(2)25^(@)+sin^(2)65^(@)))-(2cos^(2)60tan^(2)28^(@)tan^(2)62)/(3(sec^(2)43^(@)-cot^(2)47^(@)))

Evaluate: (sec^(2)(90^(@) - theta)-cot^(2) theta)/(2 (sin^(2) 25^(@)+sin^(2) 65^(@)))+(2 sin^(2)30^(@)tan^(2) 32^(@) tan^(2)58^(@))/(3(sec^(2)33^(@)-cot^(2)57^(@))) .

Evaluate : (sec^(2)theta-cot^(2)(90^(@)-theta))/("cosec"^(2)67^(@)-tan^(2)23^(2))+(sin^(2)40^(@)+sin^(2)50^(@))

Evaluate : (sec^(2)theta-cot^(2)(90^(@)-theta))/("cosec"^(2)67^(@)-tan^(2)23^(2))+(sin^(2)40^(@)+sin^(2)50^(@))

The value of cottheta.tan(90^(@)-theta)-sec(90^(@)-theta)cosectheta+(sin^(2)25^(@)+sin^(2)65^(@)) is

(sec^(2)theta-sin^(2)theta)/(tan^(2)theta)=cosec^(2)theta-cos^(2)theta

Prove the following: cot^2 theta - tan^2 theta = cosec^2 theta - sec^2 theta

Prove the following : cot^2 theta - tan^2 theta = cosec^2 theta -sec^2 theta

Evaluate the following determinants |{:(-cos^2 theta,sec^2 theta),(cot^2 theta,-tan^2 theta):}|