The uncertainty in position and velocity of the particle are `0.2mm` and `10.54xx10^(-27)ms^(-1)` respectively then the mass of the particle is `: ( h=6.625xx10^(-34)Js)`

Options

A. `48.86g`
B. `30.86g`
C. `24.86gm`
D. `100g`

Answer

3

Explanation

`Deltax=0.2 xx10^(-9)m`.
`DeltaV=10.54xx10^(-27)ms^(-1)`
`:. " "Deltax xxmDeltaV=(h)/(4pi)`
`:." "0.2xx10^(-3)xxmxx10.54xx10^(-27)=0.527xx10^(-34)`
`m=24.86gm`