Home
Class 12
CHEMISTRY
The solubility of Mg(OH)(2) in pure wate...

The solubility of `Mg(OH)_(2)` in pure water is `9.57xx10^(-3)`g `litre^(-1)`. Calculate the pH of its saturated solution. (Assume `100%` ionisation)

Text Solution

Verified by Experts

The correct Answer is:
`8.7xx10^(-4)gL^(-1))`
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL AND IONIC EQUILIBRIUM

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise OBJECTIVE_TYPE|3 Videos
  • CHEMICAL AND IONIC EQUILIBRIUM

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise COMPREHENSION_TYPE|3 Videos
  • CARBOXYLIC ACID AND THEIR DERIVATIVES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise CHAPTER TEST|3 Videos
  • CHEMICAL BONDING

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise MATCH THE COLUMN|1 Videos

Similar Questions

Explore conceptually related problems

The solubility of Mg (OH)_(2) in pure water is 9.57 xx 10^(-3) gL^(-1) . Calculate its solubility (in gL^(-1)) in 0.02M Mg(NO_(3))_(2) solution.

The solubility of Pb(OH)_(2) in water is 6.7xx10^(-6) M. Calculate the solubility of Pb(OH)_(2) in a buffer solution of pH=8 .

Solubility of Cd(OH)_(2) in pure water is 1.84xx10^(-5)"mole"//L Calculate its solubility in a buffer solution of ph=12 .

The solubility of Mg(OH)_(2) " is " 8.352 xx 10^(-3) g L^(-1) at 298 K. Calculate the K_(sp) of Mg(OH)_(2) at this temerature.