sqrt(((1+sin2 theta))/(1-cos^(2)theta))[" where "theta in[0,(pi)/(4)]]=

sqrt(((1+sin2theta))/(1-cos^(2)theta))["where" theta in [0,(pi)/(4)]]=

If f(theta)=sin(tan^(-1)((sin theta)/(sqrt(cos2 theta)))), where -(pi)/(4)

Prove that sqrt((1-cos2 theta)/(1+cos2 theta))=tan theta where tan theta>0

Prove that sqrt((1-cos2 theta)/(1+cos2 theta))=tan theta where tan theta>0

Prove that sqrt(1+sin theta)/sqrt(1-sin theta)=sec theta + tan theta ,-(pi)/(2) lt theta lt (pi)/(2)

The value of 3(cos theta-sin theta)^(4)+6(sin theta+cos theta)^(2)+4 sin^(6) theta is where theta in ((pi)/(4),(pi)/(2))

Prove that sqrt((1-sin theta)/(1+sin theta))+sqrt((1+sin theta)/(1-sin theta))=-2/cos theta ,where pi/2ltthetaltpi .

If f(theta) = sin(tan^(-1)(("sin theta)/(sqrt(cos 2 theta)))) , where -pi/4 lt theta lt pi/4 , then the value of d/(d(tan theta)) f(theta) is

I : If sin((pi)/(4)cot theta)=cos ((pi)/(4)tan theta) then theta = n pi+pi//4, n in Z II : If tan ((pi)/(2)sin theta)=cot((pi)/(2)cos theta) then sin (theta + (pi)/(4))= pm (1)/(sqrt(2))

The solution of the equation cos^(2)theta-2cos theta=4sin theta-sin2 theta where theta in[0,pi] is