A road roller takes 750 complete revolutions to more once over to level a road. Find the area of the road if the diameter of a road under roller is 91 cm and length is 1.25 m.

Explanation

Given that
Length of roller = h = 1m
Diameter of the roller = 84 cm
Therefore, Radius of the roller(r)
`r=84/2`
`r=42 cm`
Radius of the roller = `42/100 m`
given that the roller takes` 750 `complete revolutions to level the whole road.
Therefore, the area of road =` 750` (Area covered in one revolution)
The area of road = `750 `(Lateral surface area of cylinder)
The area of road = `750xx2πrh`
The area of road = `750xx2xx22/7xx42/100xx1=750xx2xx22xx6/100`
The area of road =`(1500xx132)/100=15xx132=1980`
Hence, the area of the road is `1980m^2`