The correct curve between voltage gain `(A_(v))` and load resistance `(R_(L))` is

A zener diode voltage regulator operated in the range 120-180V produces a constant supply of 110V and 250mA. To the load.If the maximum current is to be equally shared between the load and the zener, then the values of series resistance (R_(s)) and load resistance (R_(L)) are

A transistor is connected in commono emitter configuration. The collector emitter voltage is 8 V and load resistance of 8000Omega is connected in the collector circuit the voltage drop across the load resistance is 0.5V. If the current gain be 0.96, what is the base current

In given circuit, correct curve depicting voltage across resistance R, with time is?

Draw a simple circuit of a CE transistor amplifier. Explain its working. Show that the voltage gain, A_(v) , of the amplifier is given by A_(v)= -(beta_(ac) R_(I))/(r_(i)) , where beta_(ac) is the current gain, R_(L) is the load resistance and r_(i ) is the input resistance of the transistor. What is the significance of the negative sign in the expression of the voltage gain ?

A Zener diode voltage regulator operated in the range 120 V - 180 V produces a constant supply of 110 v and 250 aM to the load . If the maximum current is equally shared between the load and the Zener diode, then the values of load resistance (R_(L)) and series resistance (R_(S)) are respectively

In a common base transistor amplifier if the input resistance R_(i) is 200 Omega and load resistance R_(L) is 20K Omega , find voltage gain (alpha=0.95)