The emf of a battery is 6.0 V and its internal resistance is `1.5 Omega`. Its potential differences is measured by a voltmeter of resistance `1000 Omega`. Calculate the percentage error in the reading of emf shown by voltmeter.

The emf of a battery is 4.0 V and its internal resistance is 1.5 Omega . Its potential difference is measured by a voltmeter of resistance 1000 Omega . Calculate the percentage error in the reading of emf shown by voltmeter.

A voltmeter of resistance 995 Omega is connected across a cell of emf 3V and internal resistance 5 Omega . Find the potential difference across the voltmeter, that across the terminals of the cell and percentage error in the reading of voltmeter.

In the circuit shown in figure-3.387, the voltmeter is having a resistance 4000 Omega . Find the percentage error in reading of this voltmeter.

A voltmeter of resistance 994Omega is connected across a cell of emf 1 V and internal resistance 6Omega . Find the potential difference across the voltmeter, that across the terminals of the cell and percantage error in the reading of the voltmeter.

A voltmeter of resistance 994Omega is connected across a cell of emf 1 V and internal resistance 6Omega . Find the potential difference across the voltmeter, that across the terminals of the cell and percantage error in the reading of the voltmeter.

A voltmeter resistance 500 Omega is used to measure the emf of a cell of internal resistance 4 Omega . The percentage error in the reading of the voltmeter will be

A voltmeter resistance 500 Omega is used to measure the emf of a cell of internal resistance 4 Omega . The percentage error in the reading of the voltmeter will be

A voltmeter with a resistance of 8000Omega is used to measure the emf of a cell of internal resistance 4Omega . What is the percentage error in the reading of the voltmeter?