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A deutron of kinetic energy 50 keV is de...

A deutron of kinetic energy `50` keV is describing a circular orbit of radius `0.5` meter in a plane perpendicular to magnetic field `vecB`. The kinetic energy of the proton that describes a circular orbit of radius `0.5` meter in the same plane with the same `vecB` is

A

25 KeV

B

50 KeV

C

200 KeV

D

100 KeV

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The correct Answer is:
d
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NEET PREVIOUS YEAR (YEARWISE + CHAPTERWISE)-MAGNETIC EFFECT OF CURRENT-Exercise
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