For a photosensitive surface, threshold wavelength is`lamda_(0)`. Does photoemission occur, if the wavelength `(lamda)` of the incident radiation is (a) more than `lamda_(0)` (b) less than `lamda_(0)`? Justify your answer.

The wavelength of an electromagnetic radiation is lamda . What is the energy of a photon of this radiation?

The threshold frequency and the threshold wavelength of photoelectric emission from a metal surface are f_(0) and lamda_(0) . The frequency and the wavelength of incident light are f and lamda . Then

An electromagnetic wave of wavelength lamda is incident on a photoelectrons emitted from this surface have the de Broglie wavelength lamda_(1) prove that lamda = ((2mc)/(h)) lamda_(1)^(2)

The threshold wavelength of a metal having work function W is lamda . What will be the threshold wavelength of a metal having work function 2W ?

A monochromatic radiation of wavelength lamda and intensity I is incident on a plate of area A. Find the number of photons striking the plate per second.

A metal surface does not emit any electron if the energy of incident radiation is less than the photoelectric work function of the metal - justify the statement mathematically.

A certain, metallic surface is illuminated with monochromatic light of wavelength, lamda . The stopping potential for photoelectric current for this light is 3 V_(0) . If the same surface is illuminated with light of wavelength 2lamda , the stopping potential is V_(0) . The threshold wavelength for this surface for photoelectric effect is

If the de Broglie wavelength of a gas molecule at 0^(@)C be lamda , what will be its wavelength at 819^(@)C ?

Would you expect the second electron-gain enthalpy of O as positive,more negative or less negative than the first justify your answer.

Will the concentration of H_(3)O^(+) ions in pure water at 0^(@)C be more than or less than that at 4^(@)C ?