Light from a discharge tube containing hydrogen atoms is incident on the surface of a piece of sodium . The maximum kinetic energy of the photoelectrons emitted from sodium is 0.73 eV. The work function of sodium is 1.82 eV .
(ii) The quantum numbers of the two orbits in the hydrogen atom involved in emission of photons and

Explanation

Energy difference between the two orbits is 2.55 eV. Now in case of hydrogen atom,
Energy in the ground state (n=1),`E_1=-13.6 eV`
Energy in n =2 state, `E_2=(E_1)/(2^2)=(13.6)/(4)=-3.4 eV`
Energy in n =3 state, `E_3=(E_1)/(3^2)=-(13.6)/(9)=-1.51 eV`
Energy in n =4 state, `E_4=(E_1)/(4^2)=-(13.6)/(16)=-0.85 eV`
If calculations are done up to this state , it is seen that
`E_4-E_2=2.55 eV`
So, quantum numbers of the two orbits are 4 and 2.