Calculate the total pressure in a mixture of 3.5 g of dinitrogen 3.0 g of dihydrogen and 8.0 g dioxygen confined in vessel of 5 `dm^3` at `27^@C` (R=0.083 bar `dm^3K^-1 mol^-1)`

Explanation

Number of moles of `N_2=3.5/28=0.125`
Number of moles of `H_2=3.0/2=1.5`
Number of moles of `O_2=8.0/32=0.25`
Total number moles of gaseous mixture =0.125+1.5+0.25=1.875
Substituting these values in ideal gas equation
`p=(nRT)/V`
`=(1.875mol times0.083b ardm^3K^-1mol^-1 times300K)/(5dm^3)`
=9.33 bar