In an equilibrium `A+BhArrC+D,A` and B are mixed in a vessel at temperature T. The initial concentration of A was twice the initial concentration of B. After the attainment of equilibrium, concentration of C was thrice concentration of B, calculate `K_(c)`.

Explanation

`underset(2a-x)underset(2a)(A)+underset(a-x)underset(a)(B)hArrunderset(x)underset(0)(C)+underset(x)underset(0) (D)` initial concentrations equilibrium concentrations
At equilibrium `x=3xx(a-x)`
`3a-3x=x`
`3a=4x`
`x=(3a)/4`
`K_(c)=([C][D])/([A][B])=((3a)/4xx(3a)/4)/((5a)/4xxa/4), :.K_(c)=9/5=1.8`