Home
Class 12
CHEMISTRY
In order to cause coagulation of 200 ml ...

In order to cause coagulation of 200 ml of gold sol, 585 ml 1% w/w NaCl solution having density 1.2 gm/ml was required. What will be the coagulation value of NaCl?
(Express answer in milli-moles/litre)

Text Solution

Verified by Experts

The correct Answer is:
600
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    GRB PUBLICATION|Exercise COMPREHENSION TYPE|20 Videos

  • SURFACE CHEMISTRY

    GRB PUBLICATION|Exercise MATCH THE COLUMN TYPE|8 Videos

  • SOLID STATE

    GRB PUBLICATION|Exercise All Questions|267 Videos

Similar Questions

Explore conceptually related problems

For the coagulation of 200 mL of As_(2)S_(3) solution, 10 mL of 1 M NaCl is required. What is the coagulating value of NaCl.

For the just coagultion of 250 mL of Fe(OH)_(3) sol, 2 mL of 1 M Na_(2)SO_(4) electrolyte is required. What is the coagulating value of Na_(2)SO_(4) electrolyte.

for the coagulation of 50 mL of ferric hydroxide sol 10 mL of 0.5 M KCl is required. What is the coagulation value of KCl ?

For the coagulation of 500mL of arsenious sulphide sol, 2mL of 1MNaCl is required. What is the flocculation value of NaCl ?

Find the molality of 49% (W/V) H_(2)SO_(4) solution having density 1.49gm/ml