Two identical cells each of emf 1.5V are connected in series. IF this combination of cells is connected to a resistance and a galvanometer in series, the current that flows through the circuit is 1A.If the cells are connected in parallel the current becomes 0.6 A, Determine the internal resistance of each cell.

Explanation

To find the internal resistance of each cell, we can follow these steps:

### Given Data:
- EMF of each cell, \( E = 1.5 \, \text{V} \)
- Current when cells are in series, \( I_1 = 1 \, \text{A} \)
- Current when cells are in parallel, \( I_2 = 0.6 \, \text{A} \)
- Let the internal resistance of each cell be \( r \).
- Let the external resistance be \( R \).
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