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A block of mass 0.50kg is moving with a ...

A block of mass `0.50kg` is moving with a speed of `2.00m//s` on a smooth surface. It strikes another mass of `1 kg` at rest and they move as a single body. The energy loss during the collision is

A

`0.67J`

B

`1.00J`

C

`0.16J`

D

`0.34J`

Text Solution

Verified by Experts

The correct Answer is:
A
The initial K. E. of the block is
`K_(1) = 1/2 mv^(2)=1/2xx(0.5)xx(2)^(2)=1J`
After collision , the combined mass `=0.5+1=1.5kg`
and let v be the velocity of the combined mass after collision .
`:. ` By the principle of conservation of linear momentum
`0.5xx2=(1.5)v:. v=2/3 m//s`
and the final K.E is
`K_(2) = 1/2(1.5)xx(2/3)^(2)=1/3J`
`=1-1/3 =2/3 J = 0.67J`
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