M.I. of a thin uniform rod about the axis passing through its centre and perpendicular to its length is `ML^(2)//12` . The rod is cut transversely into two halves, which are then riveted end to end.M.I. of the composite rod about the axis passing through its centre and perpendicular to its length will be

Options

A. `(Ml^(2))/(3)`
B. `(Ml^(2))/(6)`
C. `(Ml^(2))/(48)`
D. `(Ml^(2))/(24)`

Answer

C

Explanation

`I_(1)=(ML^(2))/(12), I_(2)=(M(L//2)^(2))/(12)=(ML^(2))/(48)`