A short bar magnet is placed in a horizontal plane with its axis in the magnetic merdian . Null points are found on its equitorial line (i.e., its normal bisector) at 12.5 G and the angle of dip is zero.
(i) What is the total magnetic field at points on the axis of the magnet located by the same distance (12.5 cm) as the null-points from the centre?
(ii) Locate the null points when the magnet is turned around by `180^(@)` .
Assume that the length of the magnet is negligible as compared to the distance of the null-point from the centre of the magnet.

Answer

(i)0.76 G (ii) 15.75 cm