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The heat developed in half a minute resi...

The heat developed in half a minute resistor of resistance `5 Omega` is 15,000 joule. The current through the resistor is _______

A

`5 A`

B

`100 A`

C

`40 A`

D

`10 A`

Text Solution

Verified by Experts

The correct Answer is:
D

`H=I^(2)=Rt rArr I^(2)=(H)/(Rt)`
`I^(2)=(15,000)/(5xx30)=100A`
`I=10A`
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