sin510^(@)

Evaluate: sin 510^@

sin1770^(@).cos510^(@)+cos290^(@).tan470^(@)

Prove that: cos570^(@)s in510^(0)+sin(-330^(@))cos(-390^(@))=0

cos510^(@)cos330^(@)+sin390^(@)cos120^(@)

Prove that, cos510^(@)cos330^(@)+sin390^(@)cos120^(@)=-1 .

The value of (sin(-660^(@))tan(1050^(@))sec(420^(@)))/(cos(225^(@))cos ec(315^(@))cos(510^(@)))is :

( sin (-660^(@)) tan (1050^(@)) sec (-420^(@)))/(cos(225^(@)) "cosec"(315^(@)) cos (510^(@)))=

In a given thermocouple , the temperature of cold junction is 10^(@) C , while the temperature of inversion is 510^(@) C. What will be the neutral temperature?

Prove that: cos 570^0sin 510^0+sin(-330^0)cos(-390^0)=0

(sin(-660^@)tan(1050^@).sec(420^@))/(cos(225^@)cosec(315^@)cos(510^@))=