A block of mass 1 kg is placed on a wedge shown in figure. Find out minimum coefficient of friction between wedge and block to stop the block on it.

Options

A. 0.6
B. 0.9
C. 1
D. 0.2

Answer

C

Explanation

For minimum value of `mu`, we can write
`mg sin (45^(@)) = (f_(s))_("max")`
`mg sin 45^(@) = (mu)_("min")mg cos 45^(@) mg sin 45^(@)`
`(mu)_("min")=1`