Five capacitors are connected in series ...

Five capacitors are connected in series as shown in figure with a battery of emf 20V and the point B is earthed. The potential of point A is

20V

10V

12V

Text Solution

Verified by Experts

The correct Answer is:

Use q=CV and concept of earthing

`Q=20xxC/5=4C`
Voltage across each capacitor is
`V_C = Q/C = (4C)/(C ) = 4V`
Hence , `V_A-V_B = 4+4+4=12V`
`V_A=12V " " (V_B=0)`

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