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The total mechanicla energy of a spring ...

The total mechanicla energy of a spring mass sytem in simple harmonic motion is `E=1/2momega^2 A^2`. Suppose the oscillating particle is replaced by another particle of double the mass while the amplitude `A` remains the same. The new mechanical energy will

A

become 2 E

B

become 4E

C

become `sqrt(2)E`

D

remain same

Text Solution

Verified by Experts

The correct Answer is:
D

`T=2pisqrt((m)/(k))`
`implies omega=sqrt((k)/(m)) implies k=momega^(2)`
as spring constant k remain same
`therefore`total energy `E=(1)/(2)kA^(2)` remain same.
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