A weak acid `HX` has the dissociation constant `1 xx 10^(-5)M`. It forms a salt `NaX` on reaction with alkali. The percentage hydrolysis of `0.1M` solution of `NaX` is

Options

A. `0.0001%`
B. `0.01%`
C. `0.1%`
D. `0.15%`

Answer

B

Explanation

`X^(-) + H_(2)O hArr HX + OH^(-)`
`K_(h) = (10^(-14))/(10^(-5))` so `h = sqrt((10^(-9))/(10^(-1))) = 10^(-4)`
`100 xx 10^(-4) = 10^(-2)`
so `%` of hydolysis `= 0.01%`