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Calculate the force required to stop a s...

Calculate the force required to stop a ship of mass `5xx10^(6)kg` moving at `40kmph` in a time interval of `10` minute. How far will it travel before coming to rest. (Neglect water resistance).

Text Solution

Verified by Experts

Given , `m=5xx10^(6)kg`
`v_(0)=40xx(5)/(18)=11.1ms^(-1)` `t=10xx60=600s` `v=0`, `s=?` `F=?`
Applying `v=v_(0)+at`
we get `0=(11.1)+a(600)`
`:.a=-(11.1)/(600)=-0.0185ms^(-2)`
Force required to stop the ship `=5xx10^(6)xx0.0185=9.25xx10^(4)N`
We know that,
`v^(2)=v_(0)^(2)+2as`
i.e. `0=(11.1)^(2)+2(-0.00185)S`
i.e. `s=(123.21)/(0.037)` `s=3330.0m`
i.e. `s=3.330km`.
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