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KMnO(4) reacts with oxalic acid accordin...

`KMnO_(4)` reacts with oxalic acid according to the equation
`2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) to 2Mn^(2+)+10Co_(2)+8H_(2)O`
Here, 20mL of 1.0M `KMnO_(4)` is equivalent to:

A

30mL of 0.5M `H_(2)C_(2)O_(4)` (oxalic acid)

B

50mL of `0.1MH_(2)C_(2)O_(4)` (oxalic acid)

C

20mL of 0.5M `H_(2)C_(2)O_(4)` (oxalic acid)

D

10mL of 0.1M `H_(2)C_(2)O_(4)` (oxalic acid)

Text Solution

Verified by Experts

The correct Answer is:
B
`2 xx ` moles of `KMnO_(4)=5xx` moles of oxalic acid
mmol of `KMnO_(4)=0.1xx20=2` mmol
so mmol of `H_(2)C_(2)O_(4)=(5)/(2)xx2=5` mmol.
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