d-cos x+cos2x+cos3x=0

lim_(x->0) (1-cos x cos 2x cos 3x)/ (sin^2 2x) is equal to a) 3/4 b) 7/4 c) 7/2 d) -3/4

lim_(x->0) (1-cos x cos 2x cos 3x)/ (sin^2 2x) is equal to a) 3/4 b) 7/4 c) 7/2 d) -3/4

Prove that: 1+cos2x+cos4x+cos6x=4cos x cos2x cos3x

cosx + cos2x + cos3x=0

Evaluate: ("Lim")_(x->0)(1-cosx cos2x cos3x)/(x^2)

1+ cos 2x+ cos4x + cos 6x= ............. A) 2 cos x cos 2x cos 3x B) 4 sin x cos 2x cos 3x C) 4 cos x cos 2x cos 3x D) 2 sin x cos 2x cos 3x

Evaluate : lim_(x rarr 0)(1-cosx cos2x cos3x)/(sin^2 2x) .

Differentiate the functions given w.r.t. x: cosx cos2x cos3x

cos3x+cos2x+cos x=0