One atom of an element x weight 6.643xx1...

One atom of an element `x` weight `6.643xx10^(-232)g`. Number of moles of atom in `20` kg is :

A

140

B

150

C

250

D

500

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The correct Answer is:

D

No. of atoms `= (20 xx 10^(3))/(6.6 xx 10^(-23)) = 3 xx 10^(26)` No. of moles `= (3 xx 10^(26))/(6 xx 10^(23)) = 500`

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