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A particle P is at the origin starts wit...

A particle `P` is at the origin starts with velocity `u=(2hati-4hatj)m//s` with constant acceleration `(3hati+5hatj)m//s^(2)`. After travelling for `2s` its distance from the origin is

A

10 m

B

20.6 m

C

9.8 m

D

11.7 m

Text Solution

Verified by Experts

The correct Answer is:
B
`vecu=(2hati-4hatj)m//s, overset(-)a=(3hati-5hatj)m//s^(2)`
`overset(-)s=overset(-)s_(0)+overset(-)ut+1/2 overset(-)a t^(2)=" "0+2(2hati-4hatj)+2(3hati-5hatj)=" "(10hati-18hatj)m, |overset(-)s|=sqrt((10)^(2)+(18)^(2))=20.6m`
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