A capacitor `50muF` is connected to a power source V= 220 sin 50 t (V in volt , t in second ). The value of rms current (in ampere)

Options

A. `(sqrt(10))/(0.55)A`
B. o.55 A
C. `sqrt2 A`
D. `(0.55)/(sqrt2)A`

Answer

D

Explanation

`P = i^2_2Rightarrow i_2 = sqrt (p)/(R )= sqrt(50)/(5) = sqrt10`
`V = i_2 R= (sqrt10) (5)=5sqrt(10V)`
`i_1 = (V)/(R_1+R_2) = (5sqrt10)(2+8) = sqrt(10)/(2)` Power generated in `2Omega` resistance,
therefore `P= Vi_1 R = ((sqrt10)/(2))^2xx2= 5J/s`