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x(1),x(2),x(3), . . .,x(n) is a series. ...

`x_(1),x_(2),x_(3), . . .,x_(n)` is a series. Mean and variance of this series are `overline(x)` and `sigma^(2)` respectively.
If `x_(i)` is expressed by `x_(i)'`, then the new mean will be -

A

`overline(x)-x_(i)+x_(i)'`

B

`((n-1)overline(x)+x_(i)')/(n)`

C

`(noverline(x)-x_(i)+x_(i)')/(n)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
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