Calculate the total pressure in a mixture of `4 g` of oxygen and `2 g` of hydrogen confined in a total volume of `1 L` at `0^(@)C`.

Answer

`25.49 "bar"`

Explanation

No. of mass of oxygen `= ("Mass")/("Molar mass ") = 4/32 = 0.125 ` mol
No. of moles of hydrogen `= ("Mass")/("Molar mass") = (2)/(2) = 1.0` mol
Total no. of moles `= 0.125 + 1= 1.125` mol.
According to ideal gas equation , `PV = nRT`
`n = 1.125 mol, V = 1L, T = 0 + 273 = 273 K, R = 0.083 L "bar" K^(-1) mol^(-1)`
`:. P = (nRT)/(V) = ((1.125 mol) xx (0.083 L "bar" K^(-1) mol^(-1)) (273K))/((1 L)) = 25.49 "bar"`