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Arrange the following compounds in order...

Arrange the following compounds in order of increasing dipole moment, Ethylbenzene (I), m-dichlorobenzene (II), o-dichlorobenzene (III), p-dichlorobenzene (IV)

A

I < IV < II < III

B

IV < I < II < III

C

IV < I < III < II

D

IV < II < I < III

Text Solution

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The correct Answer is:
To arrange the compounds Ethylbenzene (I), m-Dichlorobenzene (II), o-Dichlorobenzene (III), and p-Dichlorobenzene (IV) in order of increasing dipole moment, we can follow these steps: ### Step 1: Understand the structure of each compound 1. **Ethylbenzene (I)**: This compound has an ethyl group attached to a benzene ring. It is asymmetrical and has a dipole moment due to the presence of the ethyl group. 2. **m-Dichlorobenzene (II)**: In this compound, two chlorine atoms are attached to the benzene ring at the meta positions. The bond dipoles will not cancel out completely, resulting in a net dipole moment. 3. **o-Dichlorobenzene (III)**: Here, the chlorine atoms are at the ortho positions. The bond dipoles will add up, resulting in a higher dipole moment than in meta. 4. **p-Dichlorobenzene (IV)**: The chlorine atoms are in the para positions, which means the bond dipoles are opposite and cancel each other out, resulting in a dipole moment of zero. ### Step 2: Analyze the dipole moments - **p-Dichlorobenzene (IV)**: Dipole moment = 0 (due to cancellation of bond dipoles). - **Ethylbenzene (I)**: Has a dipole moment due to the asymmetry of the ethyl group. - **m-Dichlorobenzene (II)**: Has a dipole moment due to the arrangement of the chlorine atoms, which do not cancel out completely. - **o-Dichlorobenzene (III)**: Has the highest dipole moment among these compounds because the bond dipoles add up constructively. ### Step 3: Arrange in order of increasing dipole moment Based on the analysis: 1. **p-Dichlorobenzene (IV)**: 0 dipole moment (least) 2. **Ethylbenzene (I)**: Some dipole moment (next) 3. **m-Dichlorobenzene (II)**: Moderate dipole moment (more than Ethylbenzene) 4. **o-Dichlorobenzene (III)**: Highest dipole moment (most) ### Final Arrangement Thus, the order of increasing dipole moment is: **p-Dichlorobenzene (IV) < Ethylbenzene (I) < m-Dichlorobenzene (II) < o-Dichlorobenzene (III)**
To arrange the compounds Ethylbenzene (I), m-Dichlorobenzene (II), o-Dichlorobenzene (III), and p-Dichlorobenzene (IV) in order of increasing dipole moment, we can follow these steps: ### Step 1: Understand the structure of each compound 1. **Ethylbenzene (I)**: This compound has an ethyl group attached to a benzene ring. It is asymmetrical and has a dipole moment due to the presence of the ethyl group. 2. **m-Dichlorobenzene (II)**: In this compound, two chlorine atoms are attached to the benzene ring at the meta positions. The bond dipoles will not cancel out completely, resulting in a net dipole moment. 3. **o-Dichlorobenzene (III)**: Here, the chlorine atoms are at the ortho positions. The bond dipoles will add up, resulting in a higher dipole moment than in meta. 4. **p-Dichlorobenzene (IV)**: The chlorine atoms are in the para positions, which means the bond dipoles are opposite and cancel each other out, resulting in a dipole moment of zero. ...
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