The relative lowering of vapour pressure of an aqueous solution of a non-volatile solute of molecular weight 60 (which neither dissociates nor associates in the solution) is 0.018. If `K_(f)` of water is `1.86^(@)m^(-1)` the depression in freezing point will be :

Options

A. `0.93^(@)C`
B. `3.72^(@)C`
C. `1.86^(@)C`
D. `0.018^(@)C`

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Understand the given data
- Relative lowering of vapor pressure (ΔP/P₀) = 0.018
- Molecular weight of the solute (M) = 60 g/mol
- Freezing point depression constant for water (Kf) = 1.86 °C/m

### Step 2: Relate relative lowering of vapor pressure to mole fraction
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