`18xx[7+(-3)]=[18xx7]+[18xx(-3)]`

Prove that: 18x [7+ (-3)] = [18x7] + [18x (-3)]

Verify that:- 18x [7+ (-3)] = [18x7] + [18x (-3)]

Simplify: i 8xx(-15) + 8xx6 ii (-18)xx7 + (-18)xx(-4) iii 15xx(-32) + 15xx(-18) iv 16xx(-9) + (-8) xx (-9)

.Verify the following: 18times[7+(-3)],=[18times 7]+[18times(-3)]

Find each of the following products: (a) 3 xx (-1) (b) (-1) xx 225 (c) (-21) xx (-30) (d) (-316) xx (-1) (e) (-15 xx 0 xx (-18) (f) (-12) xx (-11) xx (10) (g) 9 xx (-3) xx (-6) (h) (-18) xx (-5) xx (-4) (i) (-1) xx (-2) xx (-3) xx 4 (j) (-3) xx (-6) xx (-2) xx (-1)

If a,b,c,d in R^(+) such that a+b+c=18 then the maximum value of a^(2)b^(3)c^(4) is equal to 2^(18)xx3^(2)2^(18)xx3^(3)2^(19)xx3^(2)2^(18)xx3^(3)

Simplify: (i) (7)(18) xx(-4) (ii) (-36) xx ((-5)(9))

If +=xx, - =+, xx=÷, ÷=- , then which is the correct equation out of the following? (A) 18+6-4xx2+3=114 (B) 18+6+4-2 div 3=22 (C ) 18-6xx7+2+8=63 (D) 18xx6-4+7xx8=50

Fill in the blanks i (-6)xx(........) = 6 ii (-18)xx(.......) = (-18) iii (-8) xx (-9) = (-9) xx (...) iv 7 xx (-3) = (-3) xx (…) v {(-5)x3}x(-6) = (...)xx{3xx(-6)} vi (-5)x(...)=0