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A particle of mass 2 kg located at the p...

A particle of mass `2 kg` located at the position `(hati + hatj)m` has velocity `2(hati - hatj + hatk) m//s` . Its angular momentum about Z-axis in `kg m^(2)//s` is

A

zero

B

10

C

`4sqrt(3)`

D

`4sqrt(6)`

Text Solution

Verified by Experts

The correct Answer is:
D
`vecL= vecr xx mvecV = 2 xx 2 |{:(hati, hatj, hatk),(1,1,0),(1,-1,1):}|=4(hati - hatj - 2hatk) rArr |vecL| = 4sqrt(6) kg m^(2)//s`
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